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5p^2-27p+36=0
a = 5; b = -27; c = +36;
Δ = b2-4ac
Δ = -272-4·5·36
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-3}{2*5}=\frac{24}{10} =2+2/5 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+3}{2*5}=\frac{30}{10} =3 $
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